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Home » The distance traveled is calculated by multiplying speed by time: - Leaselab

The distance traveled is calculated by multiplying speed by time: - Leaselab

📅 February 26, 2026 👤 scraface

Feb 26, 2026

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\frac{a}{b + c} + \frac{b}{a + c} + \frac{c}{a + b}
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\frac{a}{b + c} + \frac{b}{a + c} + \frac{c}{a + b} \geq \frac{3}{2}
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\frac{\frac{1}{3}}{1 - \frac{1}{3}} = \frac{\frac{1}{3}}{\frac{2}{3}}...
So the sum is \( 3 \cdot \frac{1}{2} = \frac{3}{2} \).
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h^2 + 6^2 = 10^2
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