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Home » Shocking Revelations: Deanna Burditt’s Shocking Journey That Shocked the Industry! - Leaselab

Shocking Revelations: Deanna Burditt’s Shocking Journey That Shocked the Industry! - Leaselab

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 \tan 30^\circ = \frac{1}{\sqrt{3}}

📌 Adding these values together, we have:

📌 \tan 45^\circ + \tan 30^\circ = 1 + \frac{1}{\sqrt{3}}

📌 To express this in a single fraction, find a common denominator:

📌 + \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{\sqrt{3}} + \frac{1}{\sqrt{3}} = \frac{\sqrt{3} + 1}{\sqrt{3}}

📌 To rationalize the denominator, multiply the numerator and denominator by \(\sqrt{3}\):

📌 \frac{\sqrt{3} + 1}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}(\sqrt{3} + 1)}{3} = \frac{3 + \sqrt{3}}{3}

📌 \boxed{\frac{3 + \sqrt{3}}{3}}

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An inscribed square within a circle implies that the diagonal of the s...
Let the side length of the square be \(s\). The diagonal of the square...
\text{Diagonal} = s\sqrt{2}
Setting the diagonal equal to the diameter of the circle, we have:
s\sqrt{2} = 10
Solving for \(s\), we divide both sides by \(\sqrt{2}\):
s = \frac{10}{\sqrt{2}} = 5\sqrt{2}
The area \(A\) of the square is:
A = s^2 = (5\sqrt{2})^2 = 25 \times 2 = 50
Thus, the area of the square is \(\boxed{50}\).

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