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1964 nickel value - Leaselab

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 \sum_{k=1}^{50} \frac{1}{k(k+2)} = \frac{1}{2} \sum_{k=1}^{50} \left( \frac{1}{k} - \frac{1}{k+2} \right)

📌 \frac{1}{2} \left[ \left( \frac{1}{1} - \frac{1}{3} \right) + \left( \frac{1}{2} - \frac{1}{4} \right) + \left( \frac{1}{3} - \frac{1}{5} \right) + \cdots + \left( \frac{1}{50} - \frac{1}{52} \right) \right]

📌 Most terms cancel. The surviving positive terms are \(\frac{1}{1}, \frac{1}{2}\), and the surviving negative terms are \(-\frac{1}{51}, -\frac{1}{52}\) (since \(k+2 = 51, 52\) have no positive counterparts to cancel them).

📌 \frac{1}{2} \left( 1 + \frac{1}{2} - \frac{1}{51} - \frac{1}{52} \right) = \frac{1}{2} \left( \frac{3}{2} - \left( \frac{1}{51} + \frac{1}{52} \right) \right)

📌 Compute \(\frac{1}{51} + \frac{1}{52} = \frac{52 + 51}{51 \cdot 52} = \frac{103}{2652}\)

📌 \frac{1}{2} \left( \frac{3}{2} - \frac{103}{2652} \right) = \frac{1}{2} \left( \frac{3978 - 103}{2652} \right) = \frac{1}{2} \cdot \frac{3875}{2652} = \frac{3875}{5304}

📌 Thus, the exact value of the sum is \(\boxed{\dfrac{3875}{5304}}\).

📌 Let \(x\), \(y\), and \(z\) be positive real numbers representing risk factors in a financial model, constrained by \(x + 2y + 3z = 1\). Find the minimum value of the risk exposure function \(R = \frac{1}{x} + \frac{1}{y} + \frac{1}{z}\).

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\binom{10 + 4 - 1}{4 - 1} = \binom{13}{3} = 286
Now subtract the number of solutions where at least one $ y_i > 5 $. L...
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Yet the difference is not required.
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digits × 10 registers = 200 digit-equivalents, but memory stored in by...
Assume 1 digit = 1/8 byte → 20 digits = 20/8 = 2.5 bytes per register
× 2.5 = <<10*2.5=25>>25 bytes
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But ENIAC: 25
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